If you choose a plane with the speed of 700 km/h as a transport mean, the way will take less than 3.1.

If you move from a departure point to a destination point without stops at the speed of 110 km/h, you will arrive in 19.9.

Taking into account the distance of 2191.8, the time taken for the entire trip will depend on the middle driving speed of your vehicle and will be equal to:

• at the speed of 60 km/h — 36.5
• at the speed of 90 km/h — 24.4
• at the speed of 110 km/h — 19.9

After familiarizing with a map, determine a route distance and its exact direction. The route Catasauqua - Oklahoma City (from a departure point to a destination point) is marked with a heavy line. Route details are specified on the left from the map.